4(2-2x)+10x=6(3+2x)

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Solution for 4(2-2x)+10x=6(3+2x) equation: 



4(2-2x)+10x=6(3+2x)

We move all terms to the left:

4(2-2x)+10x-(6(3+2x))=0

We add all the numbers together, and all the variables

4(-2x+2)+10x-(6(2x+3))=0

We add all the numbers together, and all the variables

10x+4(-2x+2)-(6(2x+3))=0

We multiply parentheses

10x-8x-(6(2x+3))+8=0



We calculate terms in parentheses: -(6(2x+3)), so:

6(2x+3)

We multiply parentheses

12x+18

Back to the equation:

-(12x+18)



We add all the numbers together, and all the variables

2x-(12x+18)+8=0

We get rid of parentheses

2x-12x-18+8=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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