5(5+c)=4(1+c)

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Solution for 5(5+c)=4(1+c) equation: 



5(5+c)=4(1+c)

We move all terms to the left:

5(5+c)-(4(1+c))=0

We add all the numbers together, and all the variables

5(c+5)-(4(c+1))=0

We multiply parentheses

5c-(4(c+1))+25=0



We calculate terms in parentheses: -(4(c+1)), so:

4(c+1)

We multiply parentheses

4c+4

Back to the equation:

-(4c+4)



We get rid of parentheses

5c-4c-4+25=0

We add all the numbers together, and all the variables

c+21=0

We move all terms containing c to the left, all other terms to the right

c=-21

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