5(4z-1z)+14=4z+1

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Solution for 5(4z-1z)+14=4z+1 equation: 



5(4z-1z)+14=4z+1

We move all terms to the left:

5(4z-1z)+14-(4z+1)=0

We add all the numbers together, and all the variables

5(+3z)-(4z+1)+14=0

We multiply parentheses

15z-(4z+1)+14=0

We get rid of parentheses

15z-4z-1+14=0

We add all the numbers together, and all the variables

11z+13=0

We move all terms containing z to the left, all other terms to the right

11z=-13

z=-13/11

z=-1+2/11

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