F(x)=-4/5x+11

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Solution for F(x)=-4/5x+11 equation:



(F)=-4/5F+11
We move all terms to the left:
(F)-(-4/5F+11)=0
Domain of the equation: 5F+11)!=0
F∈R
We get rid of parentheses
F+4/5F-11=0
We multiply all the terms by the denominator
F*5F-11*5F+4=0
Wy multiply elements
5F^2-55F+4=0
a = 5; b = -55; c = +4;
Δ = b2-4ac
Δ = -552-4·5·4
Δ = 2945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{2945}}{2*5}=\frac{55-\sqrt{2945}}{10} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{2945}}{2*5}=\frac{55+\sqrt{2945}}{10} $

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