5(4x-5)=1/4(80x+12)

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Solution for 5(4x-5)=1/4(80x+12) equation: 



5(4x-5)=1/4(80x+12)

We move all terms to the left:

5(4x-5)-(1/4(80x+12))=0



Domain of the equation: 4(80x+12))!=0

x∈R



We multiply parentheses

20x-(1/4(80x+12))-25=0

We multiply all the terms by the denominator


20x*4(80x+12))-(1-25*4(80x+12))=0

Wy multiply elements

80x^2(8-100x(8=0

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