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(x)=3x^2+12x+5
We move all terms to the left:
(x)-(3x^2+12x+5)=0
We get rid of parentheses
-3x^2+x-12x-5=0
We add all the numbers together, and all the variables
-3x^2-11x-5=0
a = -3; b = -11; c = -5;
Δ = b2-4ac
Δ = -112-4·(-3)·(-5)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{61}}{2*-3}=\frac{11-\sqrt{61}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{61}}{2*-3}=\frac{11+\sqrt{61}}{-6} $
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