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5(4x-5)+3=2(10x-11)
We move all terms to the left:
5(4x-5)+3-(2(10x-11))=0
We multiply parentheses
20x-(2(10x-11))-25+3=0
We calculate terms in parentheses: -(2(10x-11)), so:We add all the numbers together, and all the variables
2(10x-11)
We multiply parentheses
20x-22
Back to the equation:
-(20x-22)
20x-(20x-22)-22=0
We get rid of parentheses
20x-20x+22-22=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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