51=2(k-1)+5(k+5)

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Solution for 51=2(k-1)+5(k+5) equation: 



51=2(k-1)+5(k+5)

We move all terms to the left:

51-(2(k-1)+5(k+5))=0



We calculate terms in parentheses: -(2(k-1)+5(k+5)), so:

2(k-1)+5(k+5)

We multiply parentheses

2k+5k-2+25

We add all the numbers together, and all the variables

7k+23

Back to the equation:

-(7k+23)



We get rid of parentheses

-7k-23+51=0

We add all the numbers together, and all the variables

-7k+28=0

We move all terms containing k to the left, all other terms to the right

-7k=-28

k=-28/-7

k=+4

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