5(4x-3)-2(6-8x)+10(-2x+7)=-2(9-12x)

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Solution for 5(4x-3)-2(6-8x)+10(-2x+7)=-2(9-12x) equation:



5(4x-3)-2(6-8x)+10(-2x+7)=-2(9-12x)
We move all terms to the left:
5(4x-3)-2(6-8x)+10(-2x+7)-(-2(9-12x))=0
We add all the numbers together, and all the variables
5(4x-3)-2(-8x+6)+10(-2x+7)-(-2(-12x+9))=0
We multiply parentheses
20x+16x-20x-(-2(-12x+9))-15-12+70=0
We calculate terms in parentheses: -(-2(-12x+9)), so:
-2(-12x+9)
We multiply parentheses
24x-18
Back to the equation:
-(24x-18)
We add all the numbers together, and all the variables
16x-(24x-18)+43=0
We get rid of parentheses
16x-24x+18+43=0
We add all the numbers together, and all the variables
-8x+61=0
We move all terms containing x to the left, all other terms to the right
-8x=-61
x=-61/-8
x=7+5/8

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