6(3+h)=4(h+2)

Solution for 6(3+h)=4(h+2) equation:

6(3+h)=4(h+2)

We move all terms to the left:

6(3+h)-(4(h+2))=0

We add all the numbers together, and all the variables

6(h+3)-(4(h+2))=0

We multiply parentheses

6h-(4(h+2))+18=0


We calculate terms in parentheses: -(4(h+2)), so:

4(h+2)

We multiply parentheses

4h+8

Back to the equation:

-(4h+8)


We get rid of parentheses

6h-4h-8+18=0

We add all the numbers together, and all the variables

2h+10=0

We move all terms containing h to the left, all other terms to the right

2h=-10

h=-10/2

h=-5