5(4x-2)=4(x+3)-6

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Solution for 5(4x-2)=4(x+3)-6 equation: 



5(4x-2)=4(x+3)-6

We move all terms to the left:

5(4x-2)-(4(x+3)-6)=0

We multiply parentheses

20x-(4(x+3)-6)-10=0



We calculate terms in parentheses: -(4(x+3)-6), so:

4(x+3)-6

We multiply parentheses

4x+12-6

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

20x-4x-6-10=0

We add all the numbers together, and all the variables

16x-16=0

We move all terms containing x to the left, all other terms to the right

16x=16

x=16/16

x=1

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