5(4r+3)=75

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Solution for 5(4r+3)=75 equation: 



5(4r+3)=75

We move all terms to the left:

5(4r+3)-(75)=0

We multiply parentheses

20r+15-75=0

We add all the numbers together, and all the variables

20r-60=0

We move all terms containing r to the left, all other terms to the right

20r=60

r=60/20

r=3

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