6x-2x=5x-4x(3x-2x)

Solution for 6x-2x=5x-4x(3x-2x) equation:

6x-2x=5x-4x(3x-2x)

We move all terms to the left:

6x-2x-(5x-4x(3x-2x))=0

We add all the numbers together, and all the variables

6x-2x-(5x-4x(+x))=0

We add all the numbers together, and all the variables

4x-(5x-4x(+x))=0


We calculate terms in parentheses: -(5x-4x(+x)), so:

5x-4x(+x)

We multiply parentheses

-4x^2+5x

Back to the equation:

-(-4x^2+5x)


We get rid of parentheses

4x^2-5x+4x=0

We add all the numbers together, and all the variables

4x^2-1x=0

a = 4; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·4·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*4}=\frac{2}{8}
=1/4
$