5(4a-6)-4(1+a)=6(2a-3)

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Solution for 5(4a-6)-4(1+a)=6(2a-3) equation: 



5(4a-6)-4(1+a)=6(2a-3)

We move all terms to the left:

5(4a-6)-4(1+a)-(6(2a-3))=0

We add all the numbers together, and all the variables

5(4a-6)-4(a+1)-(6(2a-3))=0

We multiply parentheses

20a-4a-(6(2a-3))-30-4=0



We calculate terms in parentheses: -(6(2a-3)), so:

6(2a-3)

We multiply parentheses

12a-18

Back to the equation:

-(12a-18)



We add all the numbers together, and all the variables

16a-(12a-18)-34=0

We get rid of parentheses

16a-12a+18-34=0

We add all the numbers together, and all the variables

4a-16=0

We move all terms containing a to the left, all other terms to the right

4a=16

a=16/4

a=4

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