9x(7-4x)=10

Solution for 9x(7-4x)=10 equation:

9x(7-4x)=10

We move all terms to the left:

9x(7-4x)-(10)=0

We add all the numbers together, and all the variables

9x(-4x+7)-10=0

We multiply parentheses

-36x^2+63x-10=0

a = -36; b = 63; c = -10;
Δ = b2-4ac
Δ = 632-4·(-36)·(-10)
Δ = 2529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2529}=\sqrt{9*281}=\sqrt{9}*\sqrt{281}=3\sqrt{281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3\sqrt{281}}{2*-36}=\frac{-63-3\sqrt{281}}{-72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3\sqrt{281}}{2*-36}=\frac{-63+3\sqrt{281}}{-72}
$