5(4-2x)+3x=4(6-2x)-x

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Solution for 5(4-2x)+3x=4(6-2x)-x equation: 



5(4-2x)+3x=4(6-2x)-x

We move all terms to the left:

5(4-2x)+3x-(4(6-2x)-x)=0

We add all the numbers together, and all the variables

5(-2x+4)+3x-(4(-2x+6)-x)=0

We add all the numbers together, and all the variables

3x+5(-2x+4)-(4(-2x+6)-x)=0

We multiply parentheses

3x-10x-(4(-2x+6)-x)+20=0



We calculate terms in parentheses: -(4(-2x+6)-x), so:

4(-2x+6)-x

We add all the numbers together, and all the variables

-1x+4(-2x+6)

We multiply parentheses

-1x-8x+24

We add all the numbers together, and all the variables

-9x+24

Back to the equation:

-(-9x+24)



We add all the numbers together, and all the variables

-7x-(-9x+24)+20=0

We get rid of parentheses

-7x+9x-24+20=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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