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5(2x-4)=2(6-3x)
We move all terms to the left:
5(2x-4)-(2(6-3x))=0
We add all the numbers together, and all the variables
5(2x-4)-(2(-3x+6))=0
We multiply parentheses
10x-(2(-3x+6))-20=0
We calculate terms in parentheses: -(2(-3x+6)), so:We get rid of parentheses
2(-3x+6)
We multiply parentheses
-6x+12
Back to the equation:
-(-6x+12)
10x+6x-12-20=0
We add all the numbers together, and all the variables
16x-32=0
We move all terms containing x to the left, all other terms to the right
16x=32
x=32/16
x=2
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