5(4+2x)+1(8x-12)=68

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Solution for 5(4+2x)+1(8x-12)=68 equation:


Simplifying
5(4 + 2x) + 1(8x + -12) = 68
(4 * 5 + 2x * 5) + 1(8x + -12) = 68
(20 + 10x) + 1(8x + -12) = 68

Reorder the terms:
20 + 10x + 1(-12 + 8x) = 68
20 + 10x + (-12 * 1 + 8x * 1) = 68
20 + 10x + (-12 + 8x) = 68

Reorder the terms:
20 + -12 + 10x + 8x = 68

Combine like terms: 20 + -12 = 8
8 + 10x + 8x = 68

Combine like terms: 10x + 8x = 18x
8 + 18x = 68

Solving
8 + 18x = 68

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 18x = 68 + -8

Combine like terms: 8 + -8 = 0
0 + 18x = 68 + -8
18x = 68 + -8

Combine like terms: 68 + -8 = 60
18x = 60

Divide each side by '18'.
x = 3.333333333

Simplifying
x = 3.333333333

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