8(2f-4)=4(4f-8)

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Solution for 8(2f-4)=4(4f-8) equation:


Simplifying
8(2f + -4) = 4(4f + -8)

Reorder the terms:
8(-4 + 2f) = 4(4f + -8)
(-4 * 8 + 2f * 8) = 4(4f + -8)
(-32 + 16f) = 4(4f + -8)

Reorder the terms:
-32 + 16f = 4(-8 + 4f)
-32 + 16f = (-8 * 4 + 4f * 4)
-32 + 16f = (-32 + 16f)

Add '32' to each side of the equation.
-32 + 32 + 16f = -32 + 32 + 16f

Combine like terms: -32 + 32 = 0
0 + 16f = -32 + 32 + 16f
16f = -32 + 32 + 16f

Combine like terms: -32 + 32 = 0
16f = 0 + 16f
16f = 16f

Add '-16f' to each side of the equation.
16f + -16f = 16f + -16f

Combine like terms: 16f + -16f = 0
0 = 16f + -16f

Combine like terms: 16f + -16f = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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