5(4+2x)+(-8x-12)=68

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Solution for 5(4+2x)+(-8x-12)=68 equation: 



5(4+2x)+(-8x-12)=68

We move all terms to the left:

5(4+2x)+(-8x-12)-(68)=0

We add all the numbers together, and all the variables

5(2x+4)+(-8x-12)-68=0

We multiply parentheses

10x+(-8x-12)+20-68=0

We get rid of parentheses

10x-8x-12+20-68=0

We add all the numbers together, and all the variables

2x-60=0

We move all terms containing x to the left, all other terms to the right

2x=60

x=60/2

x=30

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