5(3y+3)+7=3(2y+3)-8

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Solution for 5(3y+3)+7=3(2y+3)-8 equation: 



5(3y+3)+7=3(2y+3)-8

We move all terms to the left:

5(3y+3)+7-(3(2y+3)-8)=0

We multiply parentheses

15y-(3(2y+3)-8)+15+7=0



We calculate terms in parentheses: -(3(2y+3)-8), so:

3(2y+3)-8

We multiply parentheses

6y+9-8

We add all the numbers together, and all the variables

6y+1

Back to the equation:

-(6y+1)



We add all the numbers together, and all the variables

15y-(6y+1)+22=0

We get rid of parentheses

15y-6y-1+22=0

We add all the numbers together, and all the variables

9y+21=0

We move all terms containing y to the left, all other terms to the right

9y=-21

y=-21/9

y=-2+1/3

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