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5/2x-1=2x+4
We move all terms to the left:
5/2x-1-(2x+4)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-2x-4-1=0
We multiply all the terms by the denominator
-2x*2x-4*2x-1*2x+5=0
Wy multiply elements
-4x^2-8x-2x+5=0
We add all the numbers together, and all the variables
-4x^2-10x+5=0
a = -4; b = -10; c = +5;
Δ = b2-4ac
Δ = -102-4·(-4)·5
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6\sqrt{5}}{2*-4}=\frac{10-6\sqrt{5}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6\sqrt{5}}{2*-4}=\frac{10+6\sqrt{5}}{-8} $
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