5(3y+2)=6-2(y-2)

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Solution for 5(3y+2)=6-2(y-2) equation: 



5(3y+2)=6-2(y-2)

We move all terms to the left:

5(3y+2)-(6-2(y-2))=0

We multiply parentheses

15y-(6-2(y-2))+10=0



We calculate terms in parentheses: -(6-2(y-2)), so:

6-2(y-2)

determiningTheFunctionDomain
-2(y-2)+6

We multiply parentheses

-2y+4+6

We add all the numbers together, and all the variables

-2y+10

Back to the equation:

-(-2y+10)



We get rid of parentheses

15y+2y-10+10=0

We add all the numbers together, and all the variables

17y=0

y=0/17

y=0

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