5(3x-4)=4x+20

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Solution for 5(3x-4)=4x+20 equation: 



5(3x-4)=4x+20

We move all terms to the left:

5(3x-4)-(4x+20)=0

We multiply parentheses

15x-(4x+20)-20=0

We get rid of parentheses

15x-4x-20-20=0

We add all the numbers together, and all the variables

11x-40=0

We move all terms containing x to the left, all other terms to the right

11x=40

x=40/11

x=3+7/11

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