4x*12+x*x*2=528

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Solution for 4x*12+x*x*2=528 equation:



4x*12+x*x*2=528
We move all terms to the left:
4x*12+x*x*2-(528)=0
Wy multiply elements
2x^2*2+48x-528=0
Wy multiply elements
4x^2+48x-528=0
a = 4; b = 48; c = -528;
Δ = b2-4ac
Δ = 482-4·4·(-528)
Δ = 10752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{10752}=\sqrt{256*42}=\sqrt{256}*\sqrt{42}=16\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-16\sqrt{42}}{2*4}=\frac{-48-16\sqrt{42}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+16\sqrt{42}}{2*4}=\frac{-48+16\sqrt{42}}{8} $

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