5(3x-4)+30=1+4(x+5)

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Solution for 5(3x-4)+30=1+4(x+5) equation: 



5(3x-4)+30=1+4(x+5)

We move all terms to the left:

5(3x-4)+30-(1+4(x+5))=0

We multiply parentheses

15x-(1+4(x+5))-20+30=0



We calculate terms in parentheses: -(1+4(x+5)), so:

1+4(x+5)

determiningTheFunctionDomain
4(x+5)+1

We multiply parentheses

4x+20+1

We add all the numbers together, and all the variables

4x+21

Back to the equation:

-(4x+21)



We add all the numbers together, and all the variables

15x-(4x+21)+10=0

We get rid of parentheses

15x-4x-21+10=0

We add all the numbers together, and all the variables

11x-11=0

We move all terms containing x to the left, all other terms to the right

11x=11

x=11/11

x=1

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