1/3(x-15)=-1/6(48+2x)

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Solution for 1/3(x-15)=-1/6(48+2x) equation: 



1/3(x-15)=-1/6(48+2x)

We move all terms to the left:

1/3(x-15)-(-1/6(48+2x))=0



Domain of the equation: 3(x-15)!=0

x∈R





Domain of the equation: 6(48+2x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(x-15)-(-1/6(2x+48))=0

We calculate fractions


(6x2/(3(x-15)*6(2x+48)))+(-(-3xx)/(3(x-15)*6(2x+48)))=0



We calculate terms in parentheses: +(6x2/(3(x-15)*6(2x+48))), so:

6x2/(3(x-15)*6(2x+48))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-(-3xx)/(3(x-15)*6(2x+48))), so:

-(-3xx)/(3(x-15)*6(2x+48))

We multiply all the terms by the denominator


-(-3xx)

We get rid of parentheses

3xx

Back to the equation:

+(3xx)

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