6(x+5)+2=8(2x+5)+22

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Solution for 6(x+5)+2=8(2x+5)+22 equation: 



6(x+5)+2=8(2x+5)+22

We move all terms to the left:

6(x+5)+2-(8(2x+5)+22)=0

We multiply parentheses

6x-(8(2x+5)+22)+30+2=0



We calculate terms in parentheses: -(8(2x+5)+22), so:

8(2x+5)+22

We multiply parentheses

16x+40+22

We add all the numbers together, and all the variables

16x+62

Back to the equation:

-(16x+62)



We add all the numbers together, and all the variables

6x-(16x+62)+32=0

We get rid of parentheses

6x-16x-62+32=0

We add all the numbers together, and all the variables

-10x-30=0

We move all terms containing x to the left, all other terms to the right

-10x=30

x=30/-10

x=-3

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