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5(3x-12)+15=2(5x+12)+1
We move all terms to the left:
5(3x-12)+15-(2(5x+12)+1)=0
We multiply parentheses
15x-(2(5x+12)+1)-60+15=0
We calculate terms in parentheses: -(2(5x+12)+1), so:We add all the numbers together, and all the variables
2(5x+12)+1
We multiply parentheses
10x+24+1
We add all the numbers together, and all the variables
10x+25
Back to the equation:
-(10x+25)
15x-(10x+25)-45=0
We get rid of parentheses
15x-10x-25-45=0
We add all the numbers together, and all the variables
5x-70=0
We move all terms containing x to the left, all other terms to the right
5x=70
x=70/5
x=14
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