3(x-2)=6+2x+3x

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Solution for 3(x-2)=6+2x+3x equation:



3(x-2)=6+2x+3x
We move all terms to the left:
3(x-2)-(6+2x+3x)=0
We add all the numbers together, and all the variables
3(x-2)-(5x+6)=0
We multiply parentheses
3x-(5x+6)-6=0
We get rid of parentheses
3x-5x-6-6=0
We add all the numbers together, and all the variables
-2x-12=0
We move all terms containing x to the left, all other terms to the right
-2x=12
x=12/-2
x=-6

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