3(2y+2)-20=4(5y+1)-14

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Solution for 3(2y+2)-20=4(5y+1)-14 equation: 



3(2y+2)-20=4(5y+1)-14

We move all terms to the left:

3(2y+2)-20-(4(5y+1)-14)=0

We multiply parentheses

6y-(4(5y+1)-14)+6-20=0



We calculate terms in parentheses: -(4(5y+1)-14), so:

4(5y+1)-14

We multiply parentheses

20y+4-14

We add all the numbers together, and all the variables

20y-10

Back to the equation:

-(20y-10)



We add all the numbers together, and all the variables

6y-(20y-10)-14=0

We get rid of parentheses

6y-20y+10-14=0

We add all the numbers together, and all the variables

-14y-4=0

We move all terms containing y to the left, all other terms to the right

-14y=4

y=4/-14

y=-2/7

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