5(3x-1)=7(2x+1)

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Solution for 5(3x-1)=7(2x+1) equation: 



5(3x-1)=7(2x+1)

We move all terms to the left:

5(3x-1)-(7(2x+1))=0

We multiply parentheses

15x-(7(2x+1))-5=0



We calculate terms in parentheses: -(7(2x+1)), so:

7(2x+1)

We multiply parentheses

14x+7

Back to the equation:

-(14x+7)



We get rid of parentheses

15x-14x-7-5=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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