(2x-5)=(3x-2)

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Solution for (2x-5)=(3x-2) equation: 



(2x-5)=(3x-2)

We move all terms to the left:

(2x-5)-((3x-2))=0

We get rid of parentheses

2x-((3x-2))-5=0



We calculate terms in parentheses: -((3x-2)), so:

(3x-2)

We get rid of parentheses

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

2x-3x+2-5=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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