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5(3x-1)=5(2x-4)
We move all terms to the left:
5(3x-1)-(5(2x-4))=0
We multiply parentheses
15x-(5(2x-4))-5=0
We calculate terms in parentheses: -(5(2x-4)), so:We get rid of parentheses
5(2x-4)
We multiply parentheses
10x-20
Back to the equation:
-(10x-20)
15x-10x+20-5=0
We add all the numbers together, and all the variables
5x+15=0
We move all terms containing x to the left, all other terms to the right
5x=-15
x=-15/5
x=-3
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