2u+3-2(-3u-2)=2(u-4)

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Solution for 2u+3-2(-3u-2)=2(u-4) equation: 



2u+3-2(-3u-2)=2(u-4)

We move all terms to the left:

2u+3-2(-3u-2)-(2(u-4))=0

We multiply parentheses

2u+6u-(2(u-4))+4+3=0



We calculate terms in parentheses: -(2(u-4)), so:

2(u-4)

We multiply parentheses

2u-8

Back to the equation:

-(2u-8)



We add all the numbers together, and all the variables

8u-(2u-8)+7=0

We get rid of parentheses

8u-2u+8+7=0

We add all the numbers together, and all the variables

6u+15=0

We move all terms containing u to the left, all other terms to the right

6u=-15

u=-15/6

u=-2+1/2

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