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5(3x+9)-2x=15x-2x(x-5)
We move all terms to the left:
5(3x+9)-2x-(15x-2x(x-5))=0
We add all the numbers together, and all the variables
-2x+5(3x+9)-(15x-2x(x-5))=0
We multiply parentheses
-2x+15x-(15x-2x(x-5))+45=0
We calculate terms in parentheses: -(15x-2x(x-5)), so:We add all the numbers together, and all the variables
15x-2x(x-5)
We multiply parentheses
-2x^2+15x+10x
We add all the numbers together, and all the variables
-2x^2+25x
Back to the equation:
-(-2x^2+25x)
-(-2x^2+25x)+13x+45=0
We get rid of parentheses
2x^2-25x+13x+45=0
We add all the numbers together, and all the variables
2x^2-12x+45=0
a = 2; b = -12; c = +45;
Δ = b2-4ac
Δ = -122-4·2·45
Δ = -216
Delta is less than zero, so there is no solution for the equation
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