4x+5(x+2)=109

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Solution for 4x+5(x+2)=109 equation: 



4x+5(x+2)=109

We move all terms to the left:

4x+5(x+2)-(109)=0

We multiply parentheses

4x+5x+10-109=0

We add all the numbers together, and all the variables

9x-99=0

We move all terms containing x to the left, all other terms to the right

9x=99

x=99/9

x=11

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