If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5(3x+5)+5(4x+2)+4=35x+39
We move all terms to the left:
5(3x+5)+5(4x+2)+4-(35x+39)=0
We multiply parentheses
15x+20x-(35x+39)+25+10+4=0
We get rid of parentheses
15x+20x-35x-39+25+10+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
| 12(x=7)=-3(x+2) | | x+12=x3 | | 1/4x+1/5=-2(2/3x+3) | | 9y-18=5y+20 | | 4(2x)-3=13x-2 | | 6r+15=75 | | 33=-4t-3 | | 7/2k+-6/5=-9–8/5k | | -8j+2=50 | | 27=46+2x-2 | | -8(x+9)=2(x=4) | | 8=12(7-x) | | 172-y=71 | | 15+5y=-25 | | -2x+4=-2x+x2 | | 6(x+5)-4=-7(x-2) | | 5x-2x(1+5)=28 | | -1.2+4y=5.2 | | 7x-2=10x+5 | | 7f-28=42 | | 20=-w+194 | | 279=-w+40 | | 20+8k=76 | | H(x)=(-4x-3)(x-3) | | 6+5=2n-9 | | 7^x^2=-49^x | | 5x-7=2x-4x+14 | | 7x^2=-49^x | | 5x+30=-2x | | 8x-x-7x=4 | | v−11=7 | | 20=k+2 |