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5(3x+2)-10=3+5(-2x+1)
We move all terms to the left:
5(3x+2)-10-(3+5(-2x+1))=0
We multiply parentheses
15x-(3+5(-2x+1))+10-10=0
We calculate terms in parentheses: -(3+5(-2x+1)), so:We add all the numbers together, and all the variables
3+5(-2x+1)
determiningTheFunctionDomain 5(-2x+1)+3
We multiply parentheses
-10x+5+3
We add all the numbers together, and all the variables
-10x+8
Back to the equation:
-(-10x+8)
15x-(-10x+8)=0
We get rid of parentheses
15x+10x-8=0
We add all the numbers together, and all the variables
25x-8=0
We move all terms containing x to the left, all other terms to the right
25x=8
x=8/25
x=8/25
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