(30+4x)+(100-x)+(7x)=180

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Solution for (30+4x)+(100-x)+(7x)=180 equation: 



(30+4x)+(100-x)+(7x)=180

We move all terms to the left:

(30+4x)+(100-x)+(7x)-(180)=0

We add all the numbers together, and all the variables

(4x+30)+(-1x+100)+7x-180=0

We add all the numbers together, and all the variables

7x+(4x+30)+(-1x+100)-180=0

We get rid of parentheses

7x+4x-1x+30+100-180=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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