5(3f+2)=4(4f-4)

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Solution for 5(3f+2)=4(4f-4) equation: 



5(3f+2)=4(4f-4)

We move all terms to the left:

5(3f+2)-(4(4f-4))=0

We multiply parentheses

15f-(4(4f-4))+10=0



We calculate terms in parentheses: -(4(4f-4)), so:

4(4f-4)

We multiply parentheses

16f-16

Back to the equation:

-(16f-16)



We get rid of parentheses

15f-16f+16+10=0

We add all the numbers together, and all the variables

-1f+26=0

We move all terms containing f to the left, all other terms to the right

-f=-26

f=-26/-1

f=+26

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