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(12x-3)+(5x+12)=(3x+12)
We move all terms to the left:
(12x-3)+(5x+12)-((3x+12))=0
We get rid of parentheses
12x+5x-((3x+12))-3+12=0
We calculate terms in parentheses: -((3x+12)), so:We add all the numbers together, and all the variables
(3x+12)
We get rid of parentheses
3x+12
Back to the equation:
-(3x+12)
17x-(3x+12)+9=0
We get rid of parentheses
17x-3x-12+9=0
We add all the numbers together, and all the variables
14x-3=0
We move all terms containing x to the left, all other terms to the right
14x=3
x=3/14
x=3/14
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