5(3c-2)+3=c-(12-c)

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Solution for 5(3c-2)+3=c-(12-c) equation: 



5(3c-2)+3=c-(12-c)

We move all terms to the left:

5(3c-2)+3-(c-(12-c))=0

We add all the numbers together, and all the variables

5(3c-2)-(c-(-1c+12))+3=0

We multiply parentheses

15c-(c-(-1c+12))-10+3=0



We calculate terms in parentheses: -(c-(-1c+12)), so:

c-(-1c+12)

We get rid of parentheses

c+1c-12

We add all the numbers together, and all the variables

2c-12

Back to the equation:

-(2c-12)



We add all the numbers together, and all the variables

15c-(2c-12)-7=0

We get rid of parentheses

15c-2c+12-7=0

We add all the numbers together, and all the variables

13c+5=0

We move all terms containing c to the left, all other terms to the right

13c=-5

c=-5/13

c=-5/13

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