(2x+20)(2x)(x)=850

Solution for (2x+20)(2x)(x)=850 equation:

(2x+20)(2x)(x)=850

We move all terms to the left:

(2x+20)(2x)(x)-(850)=0

We multiply parentheses

4x^2+40x-850=0

a = 4; b = 40; c = -850;
Δ = b2-4ac
Δ = 402-4·4·(-850)
Δ = 15200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15200}=\sqrt{400*38}=\sqrt{400}*\sqrt{38}=20\sqrt{38}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-20\sqrt{38}}{2*4}=\frac{-40-20\sqrt{38}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+20\sqrt{38}}{2*4}=\frac{-40+20\sqrt{38}}{8}
$