5(3b-2)+3=6-b

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Solution for 5(3b-2)+3=6-b equation: 



5(3b-2)+3=6-b

We move all terms to the left:

5(3b-2)+3-(6-b)=0

We add all the numbers together, and all the variables

5(3b-2)-(-1b+6)+3=0

We multiply parentheses

15b-(-1b+6)-10+3=0

We get rid of parentheses

15b+1b-6-10+3=0

We add all the numbers together, and all the variables

16b-13=0

We move all terms containing b to the left, all other terms to the right

16b=13

b=13/16

b=13/16

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