x+1+10=2(3x-2)

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Solution for x+1+10=2(3x-2) equation: 



x+1+10=2(3x-2)

We move all terms to the left:

x+1+10-(2(3x-2))=0

We add all the numbers together, and all the variables

x-(2(3x-2))+11=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

x-6x+4+11=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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