5(3-x)=3(x-4)-5

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Solution for 5(3-x)=3(x-4)-5 equation: 



5(3-x)=3(x-4)-5

We move all terms to the left:

5(3-x)-(3(x-4)-5)=0

We add all the numbers together, and all the variables

5(-1x+3)-(3(x-4)-5)=0

We multiply parentheses

-5x-(3(x-4)-5)+15=0



We calculate terms in parentheses: -(3(x-4)-5), so:

3(x-4)-5

We multiply parentheses

3x-12-5

We add all the numbers together, and all the variables

3x-17

Back to the equation:

-(3x-17)



We get rid of parentheses

-5x-3x+17+15=0

We add all the numbers together, and all the variables

-8x+32=0

We move all terms containing x to the left, all other terms to the right

-8x=-32

x=-32/-8

x=+4

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