(x+3)(x-2)=3(x-1)(x+5)-2(x2+1)

Solution for (x+3)(x-2)=3(x-1)(x+5)-2(x2+1) equation:

(x+3)(x-2)=3(x-1)(x+5)-2(x2+1)

We move all terms to the left:

(x+3)(x-2)-(3(x-1)(x+5)-2(x2+1))=0

We add all the numbers together, and all the variables

-(3(x-1)(x+5)-2(+x^2+1))+(x+3)(x-2)=0

We multiply parentheses ..

-(3(+x^2+5x-1x-5)-2(+x^2+1))+(x+3)(x-2)=0


We calculate terms in parentheses: -(3(+x^2+5x-1x-5)-2(+x^2+1)), so:

3(+x^2+5x-1x-5)-2(+x^2+1)

We multiply parentheses

3x^2-2x^2+15x-3x-15-2

We add all the numbers together, and all the variables

x^2+12x-17

Back to the equation:

-(x^2+12x-17)


We get rid of parentheses

-x^2-12x+(x+3)(x-2)+17=0

We multiply parentheses ..

-x^2+(+x^2-2x+3x-6)-12x+17=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-2x+3x-6)-12x+17=0

We get rid of parentheses

-1x^2+x^2-2x+3x-12x-6+17=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1