5(3-4x)=6-2(1-4x)

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Solution for 5(3-4x)=6-2(1-4x) equation: 



5(3-4x)=6-2(1-4x)

We move all terms to the left:

5(3-4x)-(6-2(1-4x))=0

We add all the numbers together, and all the variables

5(-4x+3)-(6-2(-4x+1))=0

We multiply parentheses

-20x-(6-2(-4x+1))+15=0



We calculate terms in parentheses: -(6-2(-4x+1)), so:

6-2(-4x+1)

determiningTheFunctionDomain
-2(-4x+1)+6

We multiply parentheses

8x-2+6

We add all the numbers together, and all the variables

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

-20x-8x-4+15=0

We add all the numbers together, and all the variables

-28x+11=0

We move all terms containing x to the left, all other terms to the right

-28x=-11

x=-11/-28

x=11/28

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