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147m^2-27=0
a = 147; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·147·(-27)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*147}=\frac{-126}{294} =-3/7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*147}=\frac{126}{294} =3/7 $
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